Print alphabets from a to z c++ program do while

C++ simple program which displays alphabets from A to Z using do while loop. This program simply start the ASCII code from capital which is 65 and keep increment the ASCII code to Z. To do this a char variable is being used and initialized it form 'A' then in while loop condition it checks till character 'Z'.


//this program will print alphabets from A-Z.
#include<iostream>
#include<conio.h>
using namespace std;
int
main()
{
//working of program
int character=0; //initializing variable of type int from zero to remove garbage value
char ch='A'; //initializing character type variable from first letter 'A'
do //loop begins and steps 1-5 repeat till ch=Z
{
character=int(ch); //1)character=int(A) =changes value of A to ascii code of type int so
// character=65
cout<<ch<<" "; //2)print ch=A
character++; //3)character=66
ch=char(character); //4)ch=char(66)=changes value of 66 to alphabet
// ch=B
}
while
(ch<='Z'); //5)check if B<=Z
getch();
}


program output

Try this code to print lower case alphabets from a to z. Hint ASCII code of  'a' is 97.

Find more example here: c++ programming examples and solutions
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